[easy]Move Zeroes

难度:简单 标题:移动零

Given an array nums, write a function to move all 0’s to the end of it while maintaining the relative order of the non-zero elements.

For example, given nums = [0, 1, 0, 3, 12], after calling your function, nums should be [1, 3, 12, 0, 0].

Note:
You must do this in-place without making a copy of the array.
Minimize the total number of operations.

把数组的零移动到末尾,不改变原有非零数字顺序。

思路

双指针,flag指向下一个非零数字存放的位置。i遍历整个数组,当遇到非零数字则复制到num[flag]的位置且flag++。遇到0则跳过。最后把num[flag]以后的所有数字都赋值为0;

代码

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public class Solution {
public void moveZeroes(int[] nums) {
int flag = 0;
for(int i = 0;i<nums.length;i++){
if(nums[i] != 0){
nums[flag] = nums[i];
flag++;
}
}
for (int i = flag;i<nums.length;i++){
nums[i] = 0;
}
return;
}
}

链接

https://leetcode.com/problems/move-zeroes/

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